Electronics Engineering Board Exam Complete Practice Test 2025

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Question: 1 / 400

What is the calculated frequency of oscillations for an LC tuned circuit with L₁ = 58.6 µH and C₁ = 300 pF?

600 kHz

1199 kHz

To find the frequency of oscillations for an LC tuned circuit, the formula used is:

\[ f = \frac{1}{2\pi\sqrt{LC}} \]

where \( f \) is the frequency in hertz, \( L \) is the inductance in henries, and \( C \) is the capacitance in farads.

First, we need to ensure that both \( L \) and \( C \) are in the correct units. In this case:

- \( L = 58.6 \, \mu H = 58.6 \times 10^{-6} \, H \)

- \( C = 300 \, pF = 300 \times 10^{-12} \, F \)

Now substituting the values into the formula:

\[

f = \frac{1}{2\pi\sqrt{(58.6 \times 10^{-6})(300 \times 10^{-12})}}

\]

Calculating the product of \( L \) and \( C \):

\[

L \times C = 58.6 \times 10^{-6} \times 300 \times 10^{-12} = 1.758

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1500 kHz

2000 kHz

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