Electronics Engineering Board Exam Complete Practice Test 2026

To determine the ripple voltage in a full-wave rectified circuit, the formula used is derived from the capacitance, load current, and supply frequency. The ripple voltage (Vr) can be calculated using the formula:

\[ V_r = \frac{I}{f \cdot C} \]

where:

- \( I \) is the load current (in amperes),

- \( f \) is the frequency of the ripple (which is twice the supply frequency for full-wave rectification),

- \( C \) is the capacitance (in farads).

In this scenario:

- The load current \( I \) is 100 mA or 0.1 A,

- The supply frequency \( f \) is 50 Hz. Since it is a full-wave rectifier, the ripple frequency will be \( 2 \times 50 = 100 \) Hz,

- The capacitance \( C \) is 500 µF, which is equal to \( 500 \times 10^{-6} \) F or \( 0.0005 \) F.

Now, we can substitute these values into the ripple voltage formula:

\[ V_r = \frac{0.1 \, A}{100 \